JEE MAIN - Chemistry (2022 - 26th June Evening Shift - No. 24)
The moles of methane required to produce 81 g of water after complete combustion is _____________ $$\times$$ 10$$-$$2 mol. [nearest integer]
Answer
225
Explanation
$$
\mathrm{CH}_4+2 \mathrm{O}_2 \rightarrow \mathrm{CO}_2+2 \mathrm{H}_2 \mathrm{O}
$$
POAC on $\mathrm{H}$ atom
$$ \begin{aligned} &\mathrm{n}_{\mathrm{CH} 4} \times 4=\mathrm{n}_{\mathrm{H} 2 \mathrm{O}} \times 2 \\\\ &\mathrm{n}_{\mathrm{CH}_4}=\frac{81}{18} \times 2 \times \frac{1}{4}=\frac{81}{36} \\\\ &\mathrm{n}_{\mathrm{CH}_4}=2.25 \\\\ &=225 \times 10^{-2} \end{aligned} $$
Nearest Integers $=225$
POAC on $\mathrm{H}$ atom
$$ \begin{aligned} &\mathrm{n}_{\mathrm{CH} 4} \times 4=\mathrm{n}_{\mathrm{H} 2 \mathrm{O}} \times 2 \\\\ &\mathrm{n}_{\mathrm{CH}_4}=\frac{81}{18} \times 2 \times \frac{1}{4}=\frac{81}{36} \\\\ &\mathrm{n}_{\mathrm{CH}_4}=2.25 \\\\ &=225 \times 10^{-2} \end{aligned} $$
Nearest Integers $=225$
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