JEE MAIN - Chemistry (2022 - 26th June Evening Shift - No. 23)
Reaction of [Co(H2O)6]2+ with excess ammonia and in the presence of oxygen results into a diamagnetic product. Number of electrons present in t2g-orbitals of the product is ___________.
Answer
6
Explanation
$\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{+2} \underset{\mathrm{O}_{2}}{\stackrel{\mathrm{NH}_{3}}{\longrightarrow}}\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{+3}+e^{-}$
$$ \mathrm{Co}^{+3} \longrightarrow 3 \mathrm{~d}^{6} $$
$\mathrm{NH}_{3}$ is a strong field ligand.
$$ 3 \mathrm{~d}^{6} \longrightarrow \mathrm{t}_{2 \mathrm{~g}}^{6} ~\mathrm{eg}^{\circ} $$
$$ \mathrm{Co}^{+3} \longrightarrow 3 \mathrm{~d}^{6} $$
$\mathrm{NH}_{3}$ is a strong field ligand.
$$ 3 \mathrm{~d}^{6} \longrightarrow \mathrm{t}_{2 \mathrm{~g}}^{6} ~\mathrm{eg}^{\circ} $$
Comments (0)
