JEE MAIN - Chemistry (2022 - 26th June Evening Shift - No. 19)
The osmotic pressure exerted by a solution prepared by dissolving 2.0 g of protein of molar mass 60 kg mol$$-$$1 in 200 mL of water at 27$$^\circ$$C is ______________ Pa. [integer value]
(use R = 0.083 L bar mol$$-$$1 K$$-$$1)
Answer
415
Explanation
$\pi=\mathrm{i} C R T \quad(\mathrm{i}=1)$
$\pi=\frac{2 \times 1000}{60 \times 10^{3} \times 200} \times .083 \times 300$
$\pi=0.00415 \mathrm{~atm}$
$\pi=415 \mathrm{~Pa}$
$\pi=\frac{2 \times 1000}{60 \times 10^{3} \times 200} \times .083 \times 300$
$\pi=0.00415 \mathrm{~atm}$
$\pi=415 \mathrm{~Pa}$
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