JEE MAIN - Chemistry (2022 - 26th July Morning Shift - No. 23)
The difference between spin only magnetic moment values of $$\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]\mathrm{Cl}_{2}$$ and $$\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right] \mathrm{Cl}_{3}$$ is ___________.
Answer
0
Explanation
$\mathrm{Co} \rightarrow 4 s^{2} 3 d^{7}$
$\mathrm{H}_{2} \mathrm{O}$ is weak field ligand.
$\mathrm{Co}^{+2} \rightarrow 3 d^{7}$
$$ \begin{aligned} \mathrm{n}=3 \quad \mu_{1} &=\sqrt{n(\mathrm{n}+2)} \\ &=\sqrt{15} \text { B.M. } \end{aligned} $$
$\mathrm{Cr} \rightarrow 4 s^{1} 3 d^{5}$
$\mathrm{Co}^{+3} \rightarrow 3 d^{3}$
$\mathrm{n}=3 \quad \mu_{2}=\sqrt{15}$ B.M.
$\mu_{1}-\mu_{2}=0$
$\mathrm{H}_{2} \mathrm{O}$ is weak field ligand.
$\mathrm{Co}^{+2} \rightarrow 3 d^{7}$
$$ \begin{aligned} \mathrm{n}=3 \quad \mu_{1} &=\sqrt{n(\mathrm{n}+2)} \\ &=\sqrt{15} \text { B.M. } \end{aligned} $$
$\mathrm{Cr} \rightarrow 4 s^{1} 3 d^{5}$
$\mathrm{Co}^{+3} \rightarrow 3 d^{3}$
$\mathrm{n}=3 \quad \mu_{2}=\sqrt{15}$ B.M.
$\mu_{1}-\mu_{2}=0$
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