JEE MAIN - Chemistry (2022 - 26th July Morning Shift - No. 15)

Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R).

Assertion (A) : Experimental reaction of $$\mathrm{CH}_{3} \mathrm{Cl}$$ with aniline and anhydrous $$\mathrm{AlCl}_{3}$$ does not give $$o$$ and $$p$$-methylaniline.

Reason (R): The $$-\mathrm{NH}_{2}$$ group of aniline becomes deactivating because of salt formation with anhydrous $$\mathrm{AlCl}_{3}$$ and hence yields $$m$$-methyl aniline as the product.

In the light of the above statements, choose the most appropriate answer from the options given below :

Both A and R are true and (R) is the correct explanation of (A).
Both A and R are true but (R) is not the correct explanation of (A).
(A) is true, but (R) is false.
(A) is false, but (R) is true.

Explanation

JEE Main 2022 (Online) 26th July Morning Shift Chemistry - Compounds Containing Nitrogen Question 85 English Explanation

Aniline does not undergo Friedel Craft reaction because the reagent AlCl3 being electron deficient acts as a Lewis acid.

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