JEE MAIN - Chemistry (2022 - 26th July Morning Shift - No. 15)
Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A) : Experimental reaction of $$\mathrm{CH}_{3} \mathrm{Cl}$$ with aniline and anhydrous $$\mathrm{AlCl}_{3}$$ does not give $$o$$ and $$p$$-methylaniline.
Reason (R): The $$-\mathrm{NH}_{2}$$ group of aniline becomes deactivating because of salt formation with anhydrous $$\mathrm{AlCl}_{3}$$ and hence yields $$m$$-methyl aniline as the product.
In the light of the above statements, choose the most appropriate answer from the options given below :
Both A and R are true and (R) is the correct explanation of (A).
Both A and R are true but (R) is not the correct explanation of (A).
(A) is true, but (R) is false.
(A) is false, but (R) is true.
Explanation
_26th_July_Morning_Shift_en_15_1.png)
Aniline does not undergo Friedel Craft reaction because the reagent AlCl3 being electron deficient acts as a Lewis acid.
Comments (0)


