JEE MAIN - Chemistry (2022 - 26th July Evening Shift - No. 17)
The spin-only magnetic moment value of the compound with strongest oxidizing ability among $$\mathrm{MnF}_{4}, \mathrm{MnF}_{3}$$ and $$\mathrm{MnF}_{2}$$ is ____________ B.M. [nearest integer]
Answer
5
Explanation
$\mathrm{MnF}_{3}$ has the strongest oxidizing ability
$$ \left[\begin{array}{l} \mathrm{E}_{\mathrm{Mn}^{+3} / \mathrm{Mn}^{+2}}^{\circ} \simeq 1.57 \mathrm{~V} \\ \& \,\,\mathrm{E}_{\mathrm{Mn}^{+4} / \mathrm{Mn}^{+2}}^{\circ} \simeq 1.2 \mathrm{~V} \end{array}\right] $$
So, spin only magnetic moment
$$ =\sqrt{4(4+2)}=\sqrt{24} \text { B.M. } $$
$\simeq 5$
$$ \left[\begin{array}{l} \mathrm{E}_{\mathrm{Mn}^{+3} / \mathrm{Mn}^{+2}}^{\circ} \simeq 1.57 \mathrm{~V} \\ \& \,\,\mathrm{E}_{\mathrm{Mn}^{+4} / \mathrm{Mn}^{+2}}^{\circ} \simeq 1.2 \mathrm{~V} \end{array}\right] $$
So, spin only magnetic moment
$$ =\sqrt{4(4+2)}=\sqrt{24} \text { B.M. } $$
$\simeq 5$
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