JEE MAIN - Chemistry (2022 - 25th June Morning Shift - No. 6)
Among the following, which is the strongest oxidizing agent?
Mn3+
Fe3+
Ti3+
Cr3+
Explanation
Strongest oxidising agent have highest reduction potential value
$$\mathrm{E}_{\mathrm{Fe}^{3+} \mid \mathrm{Fe}^{2+}}^{\circ}= + 0.77 \mathrm{~V} \quad \mathrm{E}_{\mathrm{Ti}^{3+} \mid \mathrm{Ti}^{2+}}^{\circ}=-0.37 \mathrm{~V}$$
$$\mathrm{E}^{\circ}_{\mathrm{Mn}^{+3} \mid \mathrm{Mn}^{+2}}=+1.57 \mathrm{~V} \quad \mathrm{E}^{\circ}_{\mathrm{Cr}^{3+}\mid\mathrm{Cr}^{2+}} = -0.41 \mathrm{~V}$$
$$\mathrm{Mn}^{+3}$$ is the best oxidising agent among the given series.
$$\mathrm{E}_{\mathrm{Fe}^{3+} \mid \mathrm{Fe}^{2+}}^{\circ}= + 0.77 \mathrm{~V} \quad \mathrm{E}_{\mathrm{Ti}^{3+} \mid \mathrm{Ti}^{2+}}^{\circ}=-0.37 \mathrm{~V}$$
$$\mathrm{E}^{\circ}_{\mathrm{Mn}^{+3} \mid \mathrm{Mn}^{+2}}=+1.57 \mathrm{~V} \quad \mathrm{E}^{\circ}_{\mathrm{Cr}^{3+}\mid\mathrm{Cr}^{2+}} = -0.41 \mathrm{~V}$$
$$\mathrm{Mn}^{+3}$$ is the best oxidising agent among the given series.
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