JEE MAIN - Chemistry (2022 - 25th June Morning Shift - No. 5)
Cerium (IV) has a noble gas configuration. Which of the following is correct statement about it?
It will not prefer to undergo redox reactions.
It will prefer to gain electron and act as an oxidizing agent.
It will prefer to give away an electron and behave as reducing agent.
It acts as both, oxidizing and reducing agent.
Explanation
Cerium exists in two different oxidation state $$+3$$, $$+4$$
$$ \begin{array}{ll} \mathrm{Ce}^{+4}+\mathrm{e}^{-} \rightarrow \mathrm{Ce}^{3+} & \mathrm{E}^{0}=+1.61 \mathrm{~V} \\ \mathrm{Ce}^{+3}+3 \mathrm{e}^{-} \rightarrow \mathrm{Ce} & \mathrm{E}^{0}=-2.336 \mathrm{~V} \end{array} $$
It shows $$\mathrm{Ce}^{+4}$$ acts as a strong oxidising agent & accepts electron.
$$ \begin{array}{ll} \mathrm{Ce}^{+4}+\mathrm{e}^{-} \rightarrow \mathrm{Ce}^{3+} & \mathrm{E}^{0}=+1.61 \mathrm{~V} \\ \mathrm{Ce}^{+3}+3 \mathrm{e}^{-} \rightarrow \mathrm{Ce} & \mathrm{E}^{0}=-2.336 \mathrm{~V} \end{array} $$
It shows $$\mathrm{Ce}^{+4}$$ acts as a strong oxidising agent & accepts electron.
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