JEE MAIN - Chemistry (2022 - 25th June Evening Shift - No. 22)
The neutralization occurs when 10 mL of 0.1M acid 'A' is allowed to react with 30 mL of 0.05 M base M(OH)2. The basicity of the acid 'A' is __________.
[M is a metal]
Answer
3
Explanation
Milieq of acid $A=$ Milieq of base $M(O H)_{2}$
$$ \begin{aligned} & \left(\mathrm{M} \times \mathrm{V} \times \mathrm{n}-\text { Factor }_{A}\right.=(\mathrm{M} \times \mathrm{V} \times \mathrm{n}-\text { Factor })_{\mathrm{M}(\mathrm{OH})_{2}} \\\\ & \left[\mathrm{n}-\text { Factor of } \mathrm{M}(\mathrm{OH})_{2}=2\right] \\\\ &0.1 \times 10 \times \mathrm{n} \text {-Factor }= 0.05 \times 30 \times 2 \\\\ & (\mathrm{n}-\text { Factor })_{\mathrm{A}} =3 \end{aligned} $$
Hence basicity of acid $A$ is 3.
$$ \begin{aligned} & \left(\mathrm{M} \times \mathrm{V} \times \mathrm{n}-\text { Factor }_{A}\right.=(\mathrm{M} \times \mathrm{V} \times \mathrm{n}-\text { Factor })_{\mathrm{M}(\mathrm{OH})_{2}} \\\\ & \left[\mathrm{n}-\text { Factor of } \mathrm{M}(\mathrm{OH})_{2}=2\right] \\\\ &0.1 \times 10 \times \mathrm{n} \text {-Factor }= 0.05 \times 30 \times 2 \\\\ & (\mathrm{n}-\text { Factor })_{\mathrm{A}} =3 \end{aligned} $$
Hence basicity of acid $A$ is 3.
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