JEE MAIN - Chemistry (2022 - 25th June Evening Shift - No. 1)
The minimum energy that must be possessed by photons in order to produce the photoelectric effect with platinum metal is :
[Given : The threshold frequency of platinum is 1.3 $$\times$$ 1015 s$$-$$1 and h = 6.6 $$\times$$ 10$$-$$34 J s.]
3.21 $$\times$$ 10$$-$$14 J
6.24 $$\times$$ 10$$-$$16 J
8.58 $$\times$$ 10$$-$$19 J
9.76 $$\times$$ 10$$-$$20 J
Explanation
The minimum energy possessed by photons will be equal to the work function of the metal.
$$ \therefore $$ Emin = h$$\nu $$0 J
= 6.6 $$\times$$ 10$$-$$34 $$ \times $$ 1.3 $$\times$$ 1015
= 8.58 $$\times$$ 10$$-$$19 J
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