JEE MAIN - Chemistry (2022 - 25th July Morning Shift - No. 6)
A compound ‘$$\mathrm{A}$$’ on reaction with ‘$$\mathrm{X}$$’ and ‘$$\mathrm{Y}$$’ produces the same major product but different by product '$$a$$' and '$$b^{\prime}$$. Oxidation of '$$a$$' gives a substance produced by ants.
'X' and 'Y' respectively are
$$\mathrm{KMnO}_{4} / \mathrm{H}^{+}$$ and dil. $$\mathrm{KMnO}_{4^{\prime}} \,273 \mathrm{~K}$$
$$\mathrm{KMnO}_{4}$$ (dilute), $$273 \mathrm{~K}$$ and $$\mathrm{KMnO}_{4} / \mathrm{H}^{+}$$
$$\mathrm{KMnO}_{4} / \mathrm{H}^{+}$$ and $$\mathrm{O}_{3}, \mathrm{H}_{2} \mathrm{O} / \mathrm{Zn}$$
$$\mathrm{O}_{3}, \mathrm{H}_{2} \mathrm{O} / \mathrm{Zn}$$ and $$\mathrm{KMnO}_{4} / \mathrm{H}^{+}$$
Explanation
_25th_July_Morning_Shift_en_6_2.png)
Comments (0)
