JEE MAIN - Chemistry (2022 - 25th July Morning Shift - No. 17)
Among Co3+, Ti2+, V2+ and Cr2+ ions, one if used as a reagent cannot liberate H2 from dilute mineral acid solution, its spin-only magnetic moment in gaseous state is ___________ B.M. (Nearest integer)
Answer
5
Explanation
$$\mathrm{Co}^{3+}$$ will not liberate $$\mathrm{H}_{2}$$ gas an reaction with dilute acid
$$\mathrm{E}_{\mathrm{Co}^{3+}/\mathrm{Co}^{2+}}^{\mathrm{O}}=+1.97$$
And $$\mathrm{Co}^{3+}$$ has electronic configuration $$=[\operatorname{Ar}] 3 d^{6}$$
$$\therefore 4$$ unpaired $$\mathrm{e}^{-}$$ are present in it
$$\therefore$$ Spin-only magnetic moment $$=\sqrt{4(4+2)} =4.92 \approx 5$$
$$\mathrm{E}_{\mathrm{Co}^{3+}/\mathrm{Co}^{2+}}^{\mathrm{O}}=+1.97$$
And $$\mathrm{Co}^{3+}$$ has electronic configuration $$=[\operatorname{Ar}] 3 d^{6}$$
$$\therefore 4$$ unpaired $$\mathrm{e}^{-}$$ are present in it
$$\therefore$$ Spin-only magnetic moment $$=\sqrt{4(4+2)} =4.92 \approx 5$$
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