JEE MAIN - Chemistry (2022 - 25th July Morning Shift - No. 15)
The half life for the decomposition of gaseous compound $$\mathrm{A}$$ is $$240 \mathrm{~s}$$ when the gaseous pressure was 500 Torr initially. When the pressure was 250 Torr, the half life was found to be $$4.0$$ min. The order of the reaction is ______________. (Nearest integer)
Answer
1
Explanation
$$\left(\mathrm{t}_{1 / 2}\right)_{\mathrm{A}}=240 \mathrm{~s}$$ when $$\mathrm{P}=500$$ torr
$$\left(t_{1 / 2}\right)_{A}=4 \min =4 \times 60=240$$ sec when $$P=250$$ torr
If means half-life is independent of concentration of reactant present.
$\therefore$ Order of reaction $=1$
$$\left(t_{1 / 2}\right)_{A}=4 \min =4 \times 60=240$$ sec when $$P=250$$ torr
If means half-life is independent of concentration of reactant present.
$\therefore$ Order of reaction $=1$
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