JEE MAIN - Chemistry (2022 - 25th July Evening Shift - No. 17)
For the decomposition of azomethane.
CH3N2CH3(g) $$\to$$ CH3CH3(g) + N2(g), a first order reaction, the variation in partial pressure with time at 600 K is given as
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The half life of the reaction is __________ $$\times$$ 10$$-$$5 s. [Nearest integer]
Answer
2
Explanation
For first order reaction,
$$ \begin{aligned} &\ln A=\ln A_{0}-k t \\ &\text { Hence Slope }=-k \\ &-k=-3.465 \times 10^{4} \\ &k=\frac{0.693}{t_{1 / 2}} \\ &3.465 \times 10^{4}=\frac{0.693}{t_{1 / 2}} \\ &t_{1 / 2}=2 \times 10^{-5} \mathrm{~s} \end{aligned} $$
$$ \begin{aligned} &\ln A=\ln A_{0}-k t \\ &\text { Hence Slope }=-k \\ &-k=-3.465 \times 10^{4} \\ &k=\frac{0.693}{t_{1 / 2}} \\ &3.465 \times 10^{4}=\frac{0.693}{t_{1 / 2}} \\ &t_{1 / 2}=2 \times 10^{-5} \mathrm{~s} \end{aligned} $$
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