JEE MAIN - Chemistry (2022 - 25th July Evening Shift - No. 11)
$$C{H_3} - C{H_2} - CN\mathrel{\mathop{\kern0pt\longrightarrow} \limits_{Ether}^{C{H_3}MgBr}} A\buildrel {{H_3}{O^ + }} \over \longrightarrow B\mathrel{\mathop{\kern0pt\longrightarrow} \limits_{HCl}^{Zn - Hg}} C$$
The correct structure of C is
$$C{H_3} - C{H_2} - C{H_2} - C{H_3}$$
_25th_July_Evening_Shift_en_11_1.png)
_25th_July_Evening_Shift_en_11_2.png)
$$C{H_3} - C{H_2} - CH = C{H_2}$$
Explanation
_25th_July_Evening_Shift_en_11_3.png)
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