JEE MAIN - Chemistry (2022 - 24th June Morning Shift - No. 19)
A 0.166 g sample of an organic compound was digested with conc. H2SO4 and then distilled with NaOH. The ammonia gas evolved was passed through 50.0 mL of 0.5 N H2SO4. The used acid required 30.0 mL of 0.25 N NaOH for complete neutralization. The mass percentage of nitrogen in the organic compound is ____________.
Answer
63
Explanation
Millimoles of used acid $=\frac{30 \times 0.25}{2}$
Millimoles of $\mathrm{NH}_{3}=30 \times 0.25=7.5$
Mass $\%$ of nitrogen $=\frac{7.5}{0.166} \times 10^{-3} \times 14 \times 100 \simeq 63 \%$
Millimoles of $\mathrm{NH}_{3}=30 \times 0.25=7.5$
Mass $\%$ of nitrogen $=\frac{7.5}{0.166} \times 10^{-3} \times 14 \times 100 \simeq 63 \%$
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