JEE MAIN - Chemistry (2022 - 24th June Evening Shift - No. 9)
Arrange the following carbocations in decreasing order of stability.
_24th_June_Evening_Shift_en_9_1.png)
B > A > C
A > B > C
C > B > A
C > A > B
Explanation
The given carbocations are
_24th_June_Evening_Shift_en_9_2.png)
Carbocation (A) is stabilised by hyperconjugation due to $4 \alpha$ hydrogen atoms. Carbocation (C) is also stabilised by hyperconjugation due to 4 a hydrogen atoms but destabilised by $-1$ effect of O-atom. Carbocation (B) is most stable as it is stabilised by resonance.
_24th_June_Evening_Shift_en_9_3.png)
$\therefore$ Correct decreasing order of stability is $$ \text { B }>\text { A }>\text { C } $$
Carbocation (A) is stabilised by hyperconjugation due to $4 \alpha$ hydrogen atoms. Carbocation (C) is also stabilised by hyperconjugation due to 4 a hydrogen atoms but destabilised by $-1$ effect of O-atom. Carbocation (B) is most stable as it is stabilised by resonance.
$\therefore$ Correct decreasing order of stability is $$ \text { B }>\text { A }>\text { C } $$
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