JEE MAIN - Chemistry (2022 - 24th June Evening Shift - No. 8)
Transition metal complex with highest value of crystal field splitting ($$\Delta$$0) will be :
[Cr(H2O)6]3+
[Mo(H2O)6]3+
[Fe(H2O)6]3+
[Os(H2O)6]3+
Explanation
Crystal field splitting $$\left(\Delta_{0}\right)$$ for octahedral complexes depends on oxidation state of the metal as well as to which transition series the metal belongs. For the same oxidation state, the crystal field splitting $$\left(\Delta_{0}\right)$$ increases as we move from $$3 d \rightarrow 4 d \rightarrow 5 d $$
$$\mathrm{Cr}^{3+}$$ and $$\mathrm{Fe}^{3+}$$ belong to $$3 d$$ series, $$\mathrm{Mo}^{3+}$$ belongs to $$4 d$$ series and $$\mathrm{Os}^{3+}$$ belongs to $$5 d$$ series.
Therefore crystal field splitting $$\left(\Delta_{0}\right)$$ is highest for $$\left[\mathrm{Os}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}$$.
$$\mathrm{Cr}^{3+}$$ and $$\mathrm{Fe}^{3+}$$ belong to $$3 d$$ series, $$\mathrm{Mo}^{3+}$$ belongs to $$4 d$$ series and $$\mathrm{Os}^{3+}$$ belongs to $$5 d$$ series.
Therefore crystal field splitting $$\left(\Delta_{0}\right)$$ is highest for $$\left[\mathrm{Os}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}$$.
Comments (0)
