JEE MAIN - Chemistry (2021 - 31st August Morning Shift - No. 21)
A3B2 is a sparingly soluble salt of molar mass M (g mol$$-$$1) and solubility x g L$$-$$1. The solubility product satisfies $${K_{sp}} = a{\left( {{x \over M}} \right)^5}$$. The value of a is _____________. (Integer answer)
Answer
108
Explanation
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KSP = (3s)3 (2s)2
KSP = 108 s5 & s = (x/M)
KSP = 108$${\left( {{x \over M}} \right)^5}$$
given $${K_{sp}} = a{\left( {{x \over M}} \right)^5}$$
comparing a = 108
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