JEE MAIN - Chemistry (2021 - 31st August Evening Shift - No. 9)
Spin only magnetic moment in BM of [Fe(CO)4(C2O4)]+ is :
5.92
0
1
1.73
Explanation
[Fe(CO)4(C2O4)]+
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One unpaired electron Spin only magnetic moment = $$\sqrt 3 $$ B.M. = 1.73 BM
One unpaired electron Spin only magnetic moment = $$\sqrt 3 $$ B.M. = 1.73 BM
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