JEE MAIN - Chemistry (2021 - 27th July Morning Shift - No. 2)
The oxidation states of 'P' in H4P2O7, H4P2O5 and H4P2O6, respectively, are :
7, 5 and 6
5, 4 and 3
5, 3 and 4
6, 4 and 5
Explanation
Oxidation state of P in H4P2O7, H4P2O5 and H4P2O6 is 5, 3 & 4 respectively
H4P2O7
2x + 4(+ 1) + 7 ($$-$$2) = 0
x = + 5
$${H_4}\underline {{P_2}} {O_5}$$
2x + 4(+ 1) + 5 ($$-$$2) = 0
x = + 3
$${H_4}\underline {{P_2}} {O_6}$$
2x + 4 (+ 1) + 6($$-$$2) = 0
x = +4
H4P2O7
2x + 4(+ 1) + 7 ($$-$$2) = 0
x = + 5
$${H_4}\underline {{P_2}} {O_5}$$
2x + 4(+ 1) + 5 ($$-$$2) = 0
x = + 3
$${H_4}\underline {{P_2}} {O_6}$$
2x + 4 (+ 1) + 6($$-$$2) = 0
x = +4
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