JEE MAIN - Chemistry (2021 - 27th July Evening Shift - No. 5)
Statement I : $${[Mn{(CN)_6}]^{3 - }}$$, $${[Fe{(CN)_6}]^{3 - }}$$ and $${[Co{({C_2}{O_4})_3}]^{3 - }}$$ are d2sp3 hybridised.
Statement II : $${[MnCl)_6}{]^{3 - }}$$ and $${[Fe{F_6}]^{3 - }}$$ are paramagnetic and have 4 and 5 unpaired electrons, respectively.
In the light of the above statements, choose the correct answer from the options given below :
Explanation
Hybridization of all the given complexes are given in following table.
$${[Mn{(CN)_6}]^{3 - }} \Rightarrow M{n^{3 + }}$$
CN$$-$$ is a strong field ligand.
$$\therefore$$ Pairing of electron takes place.
_27th_July_Evening_Shift_en_5_1.png)
$${[Fe{(CN)_6}]^{3 - }} \Rightarrow F{e^{3 + }}$$
CN$$-$$ is a strong ligand.
$$\therefore$$ Pairing of electron takes place.
_27th_July_Evening_Shift_en_5_2.png)
$${[Co{({C_2}{O_4})_3}]^{3 - }} \Rightarrow C{o^{3 + }}$$
$${C_2}O_4^{2 - }$$ acts as strong field ligand with Co3+.
$$\therefore$$ Pairing of electrons takes place.
_27th_July_Evening_Shift_en_5_3.png)
$${[Fe{F_6}]^{3 - }} \Rightarrow F{e^{3 + }}$$
F is a weak field ligand.
$$\therefore$$ Pairing of electron does not occurs.
_27th_July_Evening_Shift_en_5_4.png)
$${[MnC{l_6}]^{3 - }} \Rightarrow M{n^{3 + }}$$
Cl$$-$$ is a weak field ligand.
$$\therefore$$ Pairing of electron does not occurs.
_27th_July_Evening_Shift_en_5_5.png)
$${[Fe{F_6}]^{3 - }}$$ have 5 unpaired electrons and $${[MnC{l_6}]^{3 - }}$$ have 4 unpaired electrons.
So, both statement I and statement II are true.
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