JEE MAIN - Chemistry (2021 - 27th July Evening Shift - No. 15)
2SO2(g) + O2(g) $$\to$$ 2SO3(g)
The above reaction is carried out in a vessel starting with partial pressure PSO2 = 250 m bar, PO2 = 750 m bar and PSO3 = 0 bar. When the reaction is complete, the total pressure in the reaction vessel is _______ m bar. (Round off of the nearest integer).
The above reaction is carried out in a vessel starting with partial pressure PSO2 = 250 m bar, PO2 = 750 m bar and PSO3 = 0 bar. When the reaction is complete, the total pressure in the reaction vessel is _______ m bar. (Round off of the nearest integer).
Answer
875
Explanation
2SO2(g) + O2(g) $$\to$$ 2SO3(g)
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$$\therefore$$ Final total pressure = 625 + 250 = 875 m bar
$$\therefore$$ Final total pressure = 625 + 250 = 875 m bar
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