JEE MAIN - Chemistry (2021 - 27th August Morning Shift - No. 22)
When 10 mL of an aqueous solution of KMnO4 was titrated in acidic medium, equal volume of 0.1 M of an aqueous solution of ferrous sulphate was required for complete discharge of colour. The strength of KMnO4 in grams per litre is __________ $$\times$$ 10$$-$$2. (Nearest integer)
[Atomic mass of K = 39, Mn = 55, O = 16]
[Atomic mass of K = 39, Mn = 55, O = 16]
Answer
316
Explanation
Let molarity of KMnO4 = x
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(Equivalents of KMnO4 reacted) = (Equivalents of FeSO4 reacted)
$$\Rightarrow$$ (5 $$\times$$ x $$\times$$ 10 ml) = 1 $$\times$$ 0.1 $$\times$$ 10 ml
$$\Rightarrow$$ x = 0.02 M
Molar mass of KMnO4 = 158 gm/mol
$$\Rightarrow$$ Strength = (x $$\times$$ 158) = 3.16 g/l
(Equivalents of KMnO4 reacted) = (Equivalents of FeSO4 reacted)
$$\Rightarrow$$ (5 $$\times$$ x $$\times$$ 10 ml) = 1 $$\times$$ 0.1 $$\times$$ 10 ml
$$\Rightarrow$$ x = 0.02 M
Molar mass of KMnO4 = 158 gm/mol
$$\Rightarrow$$ Strength = (x $$\times$$ 158) = 3.16 g/l
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