JEE MAIN - Chemistry (2021 - 27th August Morning Shift - No. 17)
1 mol of an octahedral metal complex with formula MCl3 . 2L on reaction with excess of AgNO3 gives 1 mol of AgCl. The denticity of Ligand L is ____________. (Integer answer)
Answer
2
Explanation
MCl3 . 2L octahedral
$$\mathop {MC{l_3}.2L}\limits_{1\,mole} \buildrel {Ex.\,AgN{O_3}} \over \longrightarrow $$ 1 mole of AgCl
Its means that one Cl$$-$$ ion present in ionization sphere.
$$\therefore$$ formula = [MCl2L2]Cl
For octahedral complex coordination no. is 6
$$\therefore$$ L act as bidentate ligand
$$\mathop {MC{l_3}.2L}\limits_{1\,mole} \buildrel {Ex.\,AgN{O_3}} \over \longrightarrow $$ 1 mole of AgCl
Its means that one Cl$$-$$ ion present in ionization sphere.
$$\therefore$$ formula = [MCl2L2]Cl
For octahedral complex coordination no. is 6
$$\therefore$$ L act as bidentate ligand
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