JEE MAIN - Chemistry (2021 - 27th August Evening Shift - No. 1)
The addition of dilute NaOH to Cr3+ salt solution will give :
a solution of [Cr(OH)4]$$-$$
precipitate of Cr2O3(H2O)n
precipitate of [Cr(OH)6]3$$-$$
precipitate of Cr(OH)3
Explanation
$$C{r^{3 + }} + \mathop {NaOH}\limits_{dil.} \buildrel {} \over
\longrightarrow \mathop {C{r_2}{O_3}.{{({H_2}O)}_n}}\limits_{precipitate} $$
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