JEE MAIN - Chemistry (2021 - 26th February Morning Shift - No. 4)
Match List - I with List - II.
Choose the most appropriate answer from the options given below :
| List I Electronic configuration |
List II $${\Delta _i}H$$ in kJ $$mo{l^{ - 1}}$$ |
||
|---|---|---|---|
| (a) | $$1{s^2}2{s^2}$$ | (i) | 801 |
| (b) | $$1{s^2}2{s^2}2{p^4}$$ | (ii) | 899 |
| (c) | $$1{s^2}2{s^2}2{p^3}$$ | (iii) | 1314 |
| (d) | $$1{s^2}2{s^2}2{p^1}$$ | (iv) | 1402 |
Choose the most appropriate answer from the options given below :
(a) $$ \to $$ (i), (b) $$ \to $$ (iii), (c) $$ \to $$ (iv), (d) $$ \to $$ (iii)
(a) $$ \to $$ (iv), (b) $$ \to $$ (i), (c) $$ \to $$ (ii), (d) $$ \to $$ (iii)
(a) $$ \to $$ (ii), (b) $$ \to $$ (iii), (c) $$ \to $$ (iv), (d) $$ \to $$ (i)
(a) $$ \to $$ (i), (b) $$ \to $$ (iv), (c) $$ \to $$ (iii), (d) $$ \to $$ (ii)
Explanation
(a) 1s2 2s2 $$ \to $$ Be
(b) 1s2 2s2 2p4 $$ \to $$ O
(c) 1s2 2s2 2p3 $$ \to $$ N
(d) 1s2 2s2 2p1 $$ \to $$ B
The ionization enthalpy order is
B < Be < O < N
Be has more IE compared to B due to extra stability & N has more IE compared to oxygen due to extra stability.
Hence, N $$ \to $$ 1402 kJ/mol
O $$ \to $$ 1314 kJ/mol
B $$ \to $$ 801 kJ/mol
Be $$ \to $$ 899 kJ/mol
(b) 1s2 2s2 2p4 $$ \to $$ O
(c) 1s2 2s2 2p3 $$ \to $$ N
(d) 1s2 2s2 2p1 $$ \to $$ B
The ionization enthalpy order is
B < Be < O < N
Be has more IE compared to B due to extra stability & N has more IE compared to oxygen due to extra stability.
Hence, N $$ \to $$ 1402 kJ/mol
O $$ \to $$ 1314 kJ/mol
B $$ \to $$ 801 kJ/mol
Be $$ \to $$ 899 kJ/mol
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