JEE MAIN - Chemistry (2021 - 26th February Morning Shift - No. 17)
An exothermic reaction X $$ \to $$ Y has an activation energy 30 kJ mol$$-$$1. If energy change $$\Delta$$E during the reaction is $$-$$20 kJ, then the activation energy for the reverse reaction in kJ is ___________. (Integer answer)
Answer
50
Explanation
X $$ \to $$ Y
$$\Delta $$E = (Ea)f – (Ea)b
$$ \Rightarrow $$ – 20 = 30 – (Ea)b
$$ \Rightarrow $$ (Ea)b = 50 kJ
$$\Delta $$E = (Ea)f – (Ea)b
$$ \Rightarrow $$ – 20 = 30 – (Ea)b
$$ \Rightarrow $$ (Ea)b = 50 kJ
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