JEE MAIN - Chemistry (2021 - 26th February Evening Shift - No. 23)
The number of stereoisomers possible for [Co(ox)2(Br)(NH3)]2$$-$$ is ___________. [ox = oxalate]
Answer
3
Explanation
The coordination compound [Co(ox)2(Br)(NH3)]2$$-$$ of general formula [M(A - A)2BC] can show both geometrical and optical isomerism (stereoisomerism).
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The cis-form produces non-superimposable mirror images, i.e. enantiomeric pairs (optically active)
_26th_February_Evening_Shift_en_23_2.png)
The trans-form is optically inactive.
So, total number of stereoisomers possible
= cis( $$ \pm $$ ) + trans = 3
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