JEE MAIN - Chemistry (2021 - 26th February Evening Shift - No. 18)
If the activation energy of a reaction is 80.9 kJ mol$$-$$1, the fraction of molecules at 700 K, having enough energy to react to form
products is e$$-$$x. The value of x is __________. (Rounded off to the nearest integer) [Use R = 8.31 J K$$-$$1 mol$$-$$1]
products is e$$-$$x. The value of x is __________. (Rounded off to the nearest integer) [Use R = 8.31 J K$$-$$1 mol$$-$$1]
Answer
14
Explanation
Ea = 80.9 kJ/mol
Fraction of molecules able to cross energy barrier = e$$-$$Ea/RT = e$$-$$x
x = $${{{E_a}} \over {RT}} = {{80.9 \times 1000} \over {8.31 \times 700}} = 13.91$$
$$ \Rightarrow $$ x $$ \simeq $$ 14
Fraction of molecules able to cross energy barrier = e$$-$$Ea/RT = e$$-$$x
x = $${{{E_a}} \over {RT}} = {{80.9 \times 1000} \over {8.31 \times 700}} = 13.91$$
$$ \Rightarrow $$ x $$ \simeq $$ 14
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