JEE MAIN - Chemistry (2021 - 26th August Morning Shift - No. 6)
Given below are two statements :
Statement I : The limiting molar conductivity of KCl (strong electrolyte) is higher compared to that of CH3COOH (weak electrolyte).
Statement II : Molar conductivity decreases with decrease in concentration of electrolyte.
In the light of the above statements, choose the most appropriate answer from the options given below :
Statement I : The limiting molar conductivity of KCl (strong electrolyte) is higher compared to that of CH3COOH (weak electrolyte).
Statement II : Molar conductivity decreases with decrease in concentration of electrolyte.
In the light of the above statements, choose the most appropriate answer from the options given below :
Statement I is true but Statement II is false.
Statement I is false but Statement II is true.
Both Statement I and Statement II are true.
Both Statement I and Statement II are false.
Explanation
| Ion | $${H^ + }$$ | $${K^ + }$$ | $$C{l^ - }$$ | $$C{H_3}CO{O^ - }$$ |
|---|---|---|---|---|
| $$\Lambda _{m\,Sc{m^2}/mole}^\infty $$ | 349.8 | 73.5 | 76.3 | 40.9 |
So,
$$\Lambda _{m\,\,C{H_3}COOH}^\infty = \Lambda _{m\,\,({H^ + })}^\infty + \Lambda _{m\,\,C{H_3}CO{O^ - }}^\infty $$
= 349.8 + 40.9 = 390.7 Scm2/mole
$$\Lambda _{m\,\,KCl}^\infty = \Lambda _{m\,\,({K^ + })}^\infty + \Lambda _{m\,\,(C{l^ - })}^\infty $$
= 73.5 + 76.3 = 149.3 Scm2/mole
So, Statement I is wrong or false.
As the concentration decreases, the dilution increases which increases the degree of dissociation, thus increasing the no. of ions, which increases the molar conductance.
So Statement II is false.
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