JEE MAIN - Chemistry (2021 - 26th August Morning Shift - No. 18)
The ratio of number of water molecules in Mohr's salt and potash alum is ____________ $$\times$$ 10$$-$$1. (Integer answer)
Answer
5
Explanation
Mohr's salt : (NH4)2 Fe(SO4)2 . 6H2O
The number of water molecules in Mohr's salt = 6
Potash alum : KAl(SO4)2 . 12H2O
The number of water molecules in potash alum = 12
So ratio of number of water molecules in Mohr's salt and potash alum
$$ = {6 \over {12}}$$
$$ = {1 \over 2}$$
= 0.5
= 5 $$\times$$ 10$$-$$1
The number of water molecules in Mohr's salt = 6
Potash alum : KAl(SO4)2 . 12H2O
The number of water molecules in potash alum = 12
So ratio of number of water molecules in Mohr's salt and potash alum
$$ = {6 \over {12}}$$
$$ = {1 \over 2}$$
= 0.5
= 5 $$\times$$ 10$$-$$1
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