JEE MAIN - Chemistry (2021 - 26th August Morning Shift - No. 17)
The number of 4f electrons in the ground statement electronic configuration of Gd2+ is ___________. [Atomic number of Gd = 64]
Answer
7
Explanation
The electronic configuration of
$$_{64}Gd:[Xe]4{f^7}5{d^1}6{s^2}$$
So, the electronic configuration of
$$_{64}G{d^{2 + }}:[Xe]4{f^7}5{d^1}6{s^0}$$
i.e. the number of 4f electrons in the ground state electronic configuration of $$G{d^{2 + }}$$ is 7.
$$_{64}Gd:[Xe]4{f^7}5{d^1}6{s^2}$$
So, the electronic configuration of
$$_{64}G{d^{2 + }}:[Xe]4{f^7}5{d^1}6{s^0}$$
i.e. the number of 4f electrons in the ground state electronic configuration of $$G{d^{2 + }}$$ is 7.
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