JEE MAIN - Chemistry (2021 - 26th August Evening Shift - No. 22)
A chloro compound "A".
(i) forms aldehydes on ozonolysis followed by the hydrolysis.
(ii) when vaporized completely 1.53 g of A, gives 448 mL of vapour at STP.
The number of carbon atoms in a molecule of compound A is ___________.
(i) forms aldehydes on ozonolysis followed by the hydrolysis.
(ii) when vaporized completely 1.53 g of A, gives 448 mL of vapour at STP.
The number of carbon atoms in a molecule of compound A is ___________.
Answer
3
Explanation
448 ml of A $$\Rightarrow$$ 1.53 gm A
22400 ml of A $$\Rightarrow$$ $${{1.53} \over {448}}$$ $$\times$$ 22400 gm A = 76.5 Agm
$$\mathop {{H_3}CHC - CH - Cl}\limits_{It\,has\,3\,carbon\,atoms} \mathrel{\mathop{\kern0pt\longrightarrow} \limits_{Zn/{H_2}O}^{{O_3}}} \mathop {C{H_3} - CH = O}\limits_{Aldehyde} $$
& MM is 36 + 5 + 35.5 = 76.5
22400 ml of A $$\Rightarrow$$ $${{1.53} \over {448}}$$ $$\times$$ 22400 gm A = 76.5 Agm
$$\mathop {{H_3}CHC - CH - Cl}\limits_{It\,has\,3\,carbon\,atoms} \mathrel{\mathop{\kern0pt\longrightarrow} \limits_{Zn/{H_2}O}^{{O_3}}} \mathop {C{H_3} - CH = O}\limits_{Aldehyde} $$
& MM is 36 + 5 + 35.5 = 76.5
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