JEE MAIN - Chemistry (2021 - 26th August Evening Shift - No. 13)
In the sulphur estimation, 0.471 g of an organic compound gave 1.44 g of barium sulphate. The percentage of sulphur in the compound is ____________%. (Nearest integer)
(Atomic Mass of Ba = 137 u)
(Atomic Mass of Ba = 137 u)
Answer
42
Explanation
Molecular mass of BaSO4 = 233 g
$$\because$$ 233 BaSO4 contain $$\to$$ 32 g sulphur
$$\therefore$$ 1.44 g BaSO4 contain $$\to$$ $${{32} \over {233}}$$ $$\times$$ 1.44 g sulphur given : 0.471 g of organic compound
% of S = $${{32 \times 1.44} \over {233 \times 0.471}} \times 100 = 41.98\% \approx 42\% $$
$$\because$$ 233 BaSO4 contain $$\to$$ 32 g sulphur
$$\therefore$$ 1.44 g BaSO4 contain $$\to$$ $${{32} \over {233}}$$ $$\times$$ 1.44 g sulphur given : 0.471 g of organic compound
% of S = $${{32 \times 1.44} \over {233 \times 0.471}} \times 100 = 41.98\% \approx 42\% $$
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