JEE MAIN - Chemistry (2021 - 25th July Morning Shift - No. 7)
For the following graphs,
_25th_July_Morning_Shift_en_7_2.png)
Choose from the options given below, the correct one regarding order of reaction is :
_25th_July_Morning_Shift_en_7_2.png)
Choose from the options given below, the correct one regarding order of reaction is :
(b) Zero order (c) and (e) First order
(a) and (b) Zero order (e) First order
(b) and (d) Zero order (e) First order
(a) and (b) Zero order (c) and (e) First order
Explanation
For Zero order reactions
rate = K [Reactant]0
$$\Rightarrow$$ r = k
_25th_July_Morning_Shift_en_7_3.png)
t1/2 = $${{{{[A]}_0}} \over {2K}}$$ for Zero order
_25th_July_Morning_Shift_en_7_4.png)
For First order reaction $$\to$$
r = K [Concentration]
_25th_July_Morning_Shift_en_7_5.png)
Reactant concentration after time t $$\to$$
Ct = C0 e-kt
_25th_July_Morning_Shift_en_7_6.png)
rate = K [Reactant]0
$$\Rightarrow$$ r = k
_25th_July_Morning_Shift_en_7_3.png)
t1/2 = $${{{{[A]}_0}} \over {2K}}$$ for Zero order
_25th_July_Morning_Shift_en_7_4.png)
For First order reaction $$\to$$
r = K [Concentration]
_25th_July_Morning_Shift_en_7_5.png)
Reactant concentration after time t $$\to$$
Ct = C0 e-kt
_25th_July_Morning_Shift_en_7_6.png)
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