JEE MAIN - Chemistry (2021 - 25th July Morning Shift - No. 22)
When 10 mL of an aqueous solution of Fe2+ ions was titrated in the presence of dil H2SO4 using diphenylamine indicator, 15 mL of 0.02 M solution of K2Cr2O7 was required to get the end point. The molarity of the solution containing Fe2+ ions is x $$\times$$ 10$$-$$2 M. The value of x is __________. (Nearest integer)
Answer
18
Explanation
milli-equivalents of Fe2+ = milli-equivalents of K2Cr2O7
M $$\times$$ 10 $$\times$$ 1 = 0.02 $$\times$$ 15 $$\times$$ 6
$$ \Rightarrow $$ M = 0.18 = 18 $$\times$$ 10$$-$$2 M
M $$\times$$ 10 $$\times$$ 1 = 0.02 $$\times$$ 15 $$\times$$ 6
$$ \Rightarrow $$ M = 0.18 = 18 $$\times$$ 10$$-$$2 M
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