JEE MAIN - Chemistry (2021 - 25th July Morning Shift - No. 19)
For the reaction
A + B $$\rightleftharpoons$$ 2C
the value of equilibrium constant is 100 at 298 K. If the initial concentration of all the three species is 1 M each, then the equilibrium concentration of C is x $$\times$$ 10$$-$$1 M. The value of x is ____________. (Nearest integer)
A + B $$\rightleftharpoons$$ 2C
the value of equilibrium constant is 100 at 298 K. If the initial concentration of all the three species is 1 M each, then the equilibrium concentration of C is x $$\times$$ 10$$-$$1 M. The value of x is ____________. (Nearest integer)
Answer
25
Explanation
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$$K = {{[C]_{eq}^2} \over {{{[A]}_{eq}}{{[B]}_{eq}}}} = {{{{(1 + 2x)}^2}} \over {(1 - x)(1 - x)}}$$
$$100 = {\left( {{{1 + 2x} \over {1 - x}}} \right)^2}$$
$$\left( {{{1 + 2x} \over {1 - x}}} \right) = 10$$
$$x = {3 \over 4}$$
$$[C]{e_{q.}} = 1 + 2x$$
$$ = 1 + 2\left( {{3 \over 4}} \right)$$
= 2.5 M
= 25 $$\times$$ 10-1 M
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