JEE MAIN - Chemistry (2021 - 25th July Evening Shift - No. 23)
When 3.00 g of a substance 'X' is dissolved in 100 g of CCl4, it raises the boiling point by 0.60 K. The molar mass of the substance 'X' is ______________ g mol$$-$$1. (Nearest integer).
[Given Kb for CCl4 is 5.0 K kg mol$$-$$1]
[Given Kb for CCl4 is 5.0 K kg mol$$-$$1]
Answer
250
Explanation
$$\Delta$$Tb = Kb $$\times$$ molality
0.60 = 5 $$\times$$ $$\left( {{{3/M} \over {100/100}}} \right)$$
M = 250
0.60 = 5 $$\times$$ $$\left( {{{3/M} \over {100/100}}} \right)$$
M = 250
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