JEE MAIN - Chemistry (2021 - 25th July Evening Shift - No. 16)
A system does 200 J of work and at the same time absorbs 150 J of heat. The magnitude of the change in internal energy is ____________ J. (Nearest integer)
Answer
50
Explanation
w = $$-$$200 J, q = +150 : $$\Delta$$U = q + w
$$\Delta$$U = 150 $$-$$ 200 = $$-$$50 J
Magnitude = 50 J = |$$\Delta$$U |
$$\Delta$$U = 150 $$-$$ 200 = $$-$$50 J
Magnitude = 50 J = |$$\Delta$$U |
Comments (0)
