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JEE MAIN - Chemistry (2021 - 25th February Morning Shift - No. 4)

Identify A in the given chemical reaction.

JEE Main 2021 (Online) 25th February Morning Shift Chemistry - Hydrocarbons Question 87 English
JEE Main 2021 (Online) 25th February Morning Shift Chemistry - Hydrocarbons Question 87 English Option 1
JEE Main 2021 (Online) 25th February Morning Shift Chemistry - Hydrocarbons Question 87 English Option 2
JEE Main 2021 (Online) 25th February Morning Shift Chemistry - Hydrocarbons Question 87 English Option 3
JEE Main 2021 (Online) 25th February Morning Shift Chemistry - Hydrocarbons Question 87 English Option 4

Explanation


Mo2O3 at 773 K temperature and 10-20-atm pressure is aromatising agent.

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