JEE MAIN - Chemistry (2021 - 24th February Morning Shift - No. 11)
Identify products A and B.
_24th_February_Morning_Shift_en_11_1.png)
_24th_February_Morning_Shift_en_11_1.png)
_24th_February_Morning_Shift_en_11_2.png)
_24th_February_Morning_Shift_en_11_3.png)
_24th_February_Morning_Shift_en_11_4.png)
_24th_February_Morning_Shift_en_11_5.png)
Explanation
In first step, KMnO4(dil.) help to break alkene in ketone and aldehyde and in second step, CrO3 is used for selective over oxidation of aldehyde only. CrO3 will form aldehyde to acid in product (B).
_24th_February_Morning_Shift_en_11_6.png)
_24th_February_Morning_Shift_en_11_6.png)
Comments (0)
