JEE MAIN - Chemistry (2021 - 24th February Morning Shift - No. 10)
'A' and 'B' in the following reactions are :
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_24th_February_Morning_Shift_en_10_2.png)
_24th_February_Morning_Shift_en_10_3.png)
_24th_February_Morning_Shift_en_10_4.png)
_24th_February_Morning_Shift_en_10_5.png)
Explanation
Step 1 : In step 1, NaNO2 + HCl , 0-5°C used for diazotisation reaction. It will form diazonium salt. Further, it will react with KCN to form cyanobenzene.
_24th_February_Morning_Shift_en_10_6.png)
Step 2 : In step 2, SnCl2 and HCl is a Stephen’s reduction reagent. Cyanobenzene reduced to benzaldehyde by SnCl2/HCl.
_24th_February_Morning_Shift_en_10_7.png)
Step 2 : In step 2, SnCl2 and HCl is a Stephen’s reduction reagent. Cyanobenzene reduced to benzaldehyde by SnCl2/HCl.
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