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JEE MAIN - Chemistry (2021 - 22th July Evening Shift - No. 23)

If the concentration of glucose (C6H12O6) in blood is 0.72 g L$$-$$1, the molarity of glucose in blood is ____________ $$\times$$ 10$$-$$3 M. (Nearest integer)

[Given : Atomic mass of C = 12, H = 1, O = 16 u]
Answer
4

Explanation

[Glucose] = $${{C(gm/l)} \over {M(gm/mol)}} = {{0.72} \over {180}} = 4 \times {10^{ - 3}}$$ M

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