JEE MAIN - Chemistry (2021 - 22th July Evening Shift - No. 16)
Methylation of 10 g of benzene gave 9.2 g of toluene. Calculate the percentage yield of toluene __________. (Nearest integer)
Answer
78
Explanation
$${C_6}{H_6} + C{H_3}Cl\mathrel{\mathop{\kern0pt\longrightarrow}
\limits_{}} {C_6}{H_5}C{H_3} + HCl$$
10 gm of C6H6 = $${{10} \over {78}}$$ mole
Moles of methylbenzene should be obtained = $${{10} \over {78}}$$ mole
= $$\left( {{{10} \over {78}} \times 92} \right)gm $$
$$ \therefore $$ $${{{A_y}} \over {{T_y}}} = \% $$ yield $$ = {{9.2} \over {920}} \times 78 \times 100 \Rightarrow 78\% $$
10 gm of C6H6 = $${{10} \over {78}}$$ mole
Moles of methylbenzene should be obtained = $${{10} \over {78}}$$ mole
= $$\left( {{{10} \over {78}} \times 92} \right)gm $$
$$ \therefore $$ $${{{A_y}} \over {{T_y}}} = \% $$ yield $$ = {{9.2} \over {920}} \times 78 \times 100 \Rightarrow 78\% $$
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