JEE MAIN - Chemistry (2021 - 20th July Morning Shift - No. 20)
An average person needs about 10000 kJ energy per day. The amount of glucose (molar mass = 180.0 g mol$$-$$1) needed to meet this energy requirement is ____________ g.
(Use : $$\Delta$$CH(glucose) = $$-$$2700 kJ mol$$-$$1)
(Use : $$\Delta$$CH(glucose) = $$-$$2700 kJ mol$$-$$1)
Answer
667
Explanation
1 mole glucose give 2700 kJ energy,
so mole of glucose needed for 104 kJ energy
= $${{10000} \over {2700}} = 3.703$$ moles
Weight of glucose = 3.703 $$\times$$ 180 g/moles
= 666.666
$$\approx$$ 667 g
Hence, amount of glucose required is 667 g.
so mole of glucose needed for 104 kJ energy
= $${{10000} \over {2700}} = 3.703$$ moles
Weight of glucose = 3.703 $$\times$$ 180 g/moles
= 666.666
$$\approx$$ 667 g
Hence, amount of glucose required is 667 g.
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