JEE MAIN - Chemistry (2021 - 20th July Morning Shift - No. 15)
The spin-only magnetic moment value for the complex [Co(CN)6]4$$-$$ is __________ BM.
[At. no. of Co = 27]
[At. no. of Co = 27]
Answer
2
Explanation
[Co(CN)6]4$$-$$
x + 6 $$\times$$ ($$-$$1) = $$-$$4
where, x, 6, $$-$$1 and $$-$$4 are the oxidation number of Co, number of CN ligands, charge on one CN and charge on complex.
x = +2, i.e. Co2+
Electronic configuration of Co2+ : [Ar]3d7 and CN$$-$$ is a strong field ligand which can pair electron of central atom.
_20th_July_Morning_Shift_en_15_1.png)
It has one unpaired electron (n) in 4d-subshell.
So, spin only magnetic moment ($$\mu$$) = $$\sqrt {n(n + 2)} $$ BM = $$\sqrt {1(1 + 2)} $$ BM = $$\sqrt 3 $$ BM
where, n = number of unpaired electrons
$$\mu$$ = $$\sqrt 3 $$ BM = 1.73 BM
Nearest integer = 2
x + 6 $$\times$$ ($$-$$1) = $$-$$4
where, x, 6, $$-$$1 and $$-$$4 are the oxidation number of Co, number of CN ligands, charge on one CN and charge on complex.
x = +2, i.e. Co2+
Electronic configuration of Co2+ : [Ar]3d7 and CN$$-$$ is a strong field ligand which can pair electron of central atom.
It has one unpaired electron (n) in 4d-subshell.
So, spin only magnetic moment ($$\mu$$) = $$\sqrt {n(n + 2)} $$ BM = $$\sqrt {1(1 + 2)} $$ BM = $$\sqrt 3 $$ BM
where, n = number of unpaired electrons
$$\mu$$ = $$\sqrt 3 $$ BM = 1.73 BM
Nearest integer = 2
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