JEE MAIN - Chemistry (2021 - 20th July Evening Shift - No. 24)
Potassium chlorate is prepared by electrolysis of KCl in basic solution as shown by following equation.
6OH$$-$$ + Cl$$-$$ $$\to$$ ClO3$$-$$ + 3H2O + 6e$$-$$
A current of xA has to be passed for 10h to produce 10.0g of potassium chlorate. The value of x is ____________. (Nearest integer)
(Molar mass of KClO3 = 122.6 g mol$$-$$1, F = 96500 C)
6OH$$-$$ + Cl$$-$$ $$\to$$ ClO3$$-$$ + 3H2O + 6e$$-$$
A current of xA has to be passed for 10h to produce 10.0g of potassium chlorate. The value of x is ____________. (Nearest integer)
(Molar mass of KClO3 = 122.6 g mol$$-$$1, F = 96500 C)
Answer
1
Explanation
$$W = {E \over F} \times I \times t$$
$$10 = {{122.6} \over {96500 \times 6}} \times x \times 10 \times 3600$$
$$x = 1.311$$
Ans. (1)
$$10 = {{122.6} \over {96500 \times 6}} \times x \times 10 \times 3600$$
$$x = 1.311$$
Ans. (1)
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