JEE MAIN - Chemistry (2021 - 20th July Evening Shift - No. 17)
For a given chemical reaction A $$\to$$ B at 300 K the free energy change is $$-$$49.4 kJ mol$$-$$1 and the enthalpy of reaction is 51.4 kJ mol$$-$$1. The entropy change of the reaction is _____________ JK$$-$$1 mol$$-$$1.
Answer
336
Explanation
$$\Delta$$G = $$-$$49.4 kJ/mol
$$\Delta$$H = 51.4 kJ/mol
$$\Delta$$G = $$\Delta$$H $$-$$ T$$\Delta$$S
$$-$$49400 = 51400 $$-$$ 300$$\Delta$$S
$$\Delta S = {{ + 100800} \over {300}} = 336$$ JK$$-$$1 mol$$-$$1
$$\Delta$$H = 51.4 kJ/mol
$$\Delta$$G = $$\Delta$$H $$-$$ T$$\Delta$$S
$$-$$49400 = 51400 $$-$$ 300$$\Delta$$S
$$\Delta S = {{ + 100800} \over {300}} = 336$$ JK$$-$$1 mol$$-$$1
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