JEE MAIN - Chemistry (2021 - 1st September Evening Shift - No. 4)
In the following sequence of reactions a compound A, (molecular formula C6H12O2) with a straight chain structure gives a C4 carboxylic acid. A is :
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$$C{H_3} - C{H_2} - COO - C{H_2} - C{H_2} - C{H_3}$$
_1st_September_Evening_Shift_en_4_2.png)
$$C{H_3} - C{H_2} - C{H_2} - COO - C{H_2} - C{H_3}$$
$$C{H_3} - C{H_2} - C{H_2} - O - CH = CH - C{H_2} - OH$$
Explanation
_1st_September_Evening_Shift_en_4_3.png)
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